Home
Class 11
PHYSICS
A rod of mass m and length l hinged at o...


A rod of mass `m` and length `l` hinged at one end is connected by two springs of spring constant `k_1` and `k_2` so that it is horizontal at equilibrium What is the angular frequency of the system? (in `(rad)/(s)`) (Take `l=1m`,`b=(1)/(4)m`,`K_1=16(N)/(m)`,`K_2=61(N)/(m)`.

Text Solution

Verified by Experts


Applying torque equation about
`tau_0=l_0alpha`
`k_1bthetaxxcostheta+(k_2l_theta)/(theta)xxlcostheta=-(Id^2theta)/(dt^2)`
Here `I=(ml^2)/(3)`, and as `theta` is small `costheta=1`
`(ml^2d^2theta)/(3dt^2)+(k_1b^2+k_2l^2)theta=0`
Hence, `omega=sqrt((3k_1b^2+k_2l^2)/(ml))`
On substituting the values we get `omega=8(rad)/(s)`
Promotional Banner

Topper's Solved these Questions

  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS|Exercise Subjective type|2 Videos
  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS|Exercise Multiple Correct Answer Type|6 Videos
  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS|Exercise Comprehension|33 Videos
  • KINETIC THEORY OF GASES AND FIRST LAW OF THERMODYNAMICS

    CENGAGE PHYSICS|Exercise Interger|11 Videos
  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS|Exercise Interger type|3 Videos

Similar Questions

Explore conceptually related problems

A rod of mass m and length l is connected by two spring of spring constants k_(1) and k_(2) , so that it is horizontal at equilibrium. What is the natural frequency of the system?

Two spring of spring constants k_(1) and k_(2) ar joined and are connected to a mass m as shown in the figure. Calculate the frequency of oscillation of mass m.

A horizontal rod of mass m and length L is pivoted at one end The rod's other end is supported by a spring of force constant k. The rod is displaced by a small angle theta from its horizontal equilibrium position and released. The angular frequency of the subsequent simple harmonic motion is

A block of mass m is connected between two springs (constants K_(1) and K_(2) ) as shown in the figure and is made to oscillate, the frequency of oscillation of the system shall be-

A mass M is suspended by two springs of force constants K_(1) and K_(2) respectively as shown in the diagram. The total elongation (stretch) of the two springs is

Two masses m_(1) and m_(2) are suspended from a spring of spring constant 'k'. When the masses are in equilibrium, m_(1) is gently removed. The angular frequency and amplitude of oscillation of m_(2) will be respectively

In the figure a uniform rod of mass 'm' and length 'l' is hinged at one end and the other end is connected to a light vertical of spring constant 'k' as shown in figure. The spring has extension such that rod is equilibrium when it is horizontal . The rod rotate about horizontal axis passing through end 'B' . Neglecting friction at the hinge find (a) extension in the spring (b) the force on the rod due to hinge.

A rod of length l and mass m , pivoted at one end, is held by a spring at its mid - point and a spring at far end. The spring have spring constant k . Find the frequency of small oscillations about the equilibrium position.