The equation of a progressive wave is give by `y=0.20 sin 2pi(60t-x//5)` where x and y are in metres and t is in seconds. Find the phase difference (a) between two particles separted by a distance of `Deltax=125 cm, and (b) between the two instants `(1//120 s and 1//40 s`, for any particle.

Explanation

To solve the problem step by step, we will analyze the given wave equation and calculate the phase difference for both parts of the question.

### Given Wave Equation:
The equation of the progressive wave is:
\[ y = 0.20 \sin(2\pi(60t - \frac{x}{5})) \]

### Step 1: Identify Parameters
From the wave equation, we can identify:
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