A simple harmonic progressive wave is representive by the equation `y=8 sin 2pi (0.1x -2t)` where x and y are in centimetres and t is in seconds. At any instant the phase difference between two particle separted by 2.0 cm along the x-direction is

Options

A. `18^(@)`
B. `36^(@)`
C. `54^(@)`
D. `72^(@)`

Answer

d

Explanation

`y=8 sin 2pi((x)/(10)-2t)` given by comparing with standard equation
`y=a sin2pi)(t)/(T)-(x)/(lambda))`
`lambda=10cm`
so phase difference `=(2pi//lambda)xx` path difference
`=(2pi)/(10)xx2=(2)/(5)xx180^(@)=72^(@)`