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Small amplitude progressive wave in a st...

Small amplitude progressive wave in a stretched string has a speed of `100 cm//s` and frequency 100 Hz. The phase difference between two points 2.75 cm apart on the string in radians, is

A

0

B

`11pi//2`

C

`pi//4`

D

`3pi//8`

Text Solution

Verified by Experts

The correct Answer is:
B
`v=1 m//s, v=100 Hz`
`lambda=(v)/(v)=(1)/(100)m=1 cm`
`Deltaphi=(2pi)/(lambda)xx2.75 rad=5.5 pi rad=(11pi)/(2) rad`
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