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At t=0, the shape of a travelling pulse ...

At t=0, the shape of a travelling pulse is given by
`y(x,0)=(4xx10^(-3))/(8-(x)^(-2)`
where x and y are in metres. The wave function for the travelling pulse if the velocity of propagation is `5 m//s` in the x direction is given by

A

`y(x,t)=(4xx10^(-3))/(8-(x^(2)-5t))`

B

`y(x,t)=(4xx10^(-3))/(8-(x-5t)^(2))

C

`y(x,t)=(4xx10^(-3))/(8-(x+5t)^(2))`

D

`y(x,t)=(4xx10^(-3))/(8-(x^(2)+5t))`

Text Solution

Verified by Experts

The correct Answer is:
b

`y(x,t)=f(x-vt)`
`y=(x,0)=(4xx10^(-3))/(8-x^(2))`
For a travelling wave in the `x-`direction
`y(x,t)=(4xx10^(-3))/(8-(x-5x)^(2))`
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