two particle of medium disturbed by the wave propagation are at `x_(1)=0 and x_(2)=1 cm`. The respective displacement (in cm) of the particles can be given by the equation:
`y_(1)=2 sin 3pi t, y_(2) sin (3pi t-pi//8)` the wave velocity is

Options

A. `16 cm//s`
B. `24 cm//s`
C. `12 cm//s`
D. `8 cm//s`

Answer

b

Explanation

Given `omega=3pi`
`f=(omega)/(2pi)=1.5`
Also `Deltax=1.0 cm`
Given, `phi=(2pi)/(lambda)Deltax implies(pi)/(8)=(2pi)/(lambda)xx1`
`lambda=16 cm`
`v=flambda=16xx1.5=24 cm//s`