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A progressive wave is given by y=3 si...

A progressive wave is given by
`y=3 sin 2pi [(t//0.04)-(x//0.01)]`
where x, y are in cm and t in s. the frequency of wave and maximum accelration will be:

A

`100 Hz,4.7xx10^(3) m//s^(2)`

B

`50 Hz, 7.5xx10^(3) m//s^(2)`

C

`25 Hz, 4.7xx10^(4) m//s^(2)`

D

`25 Hz, 7.5xx10^(4) m//s^(2)`

Text Solution

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The correct Answer is:
To solve the problem, we need to extract the frequency of the wave and the maximum acceleration from the given wave equation: **Given Wave Equation:** \[ y = 3 \sin \left( 2\pi \left( \frac{t}{0.04} - \frac{x}{0.01} \right) \right) \] ### Step 1: Identify the angular frequency (ω) The general form of a wave equation is: \[ y = A \sin(\omega t - kx) \] where: - \( A \) is the amplitude, - \( \omega \) is the angular frequency, - \( k \) is the wave number. From the given equation, we can see that: \[ \omega = 2\pi \left( \frac{1}{0.04} \right) \] ### Step 2: Calculate the frequency (f) The relationship between angular frequency (ω) and frequency (f) is given by: \[ \omega = 2\pi f \] Thus, we can rearrange this to find the frequency: \[ f = \frac{\omega}{2\pi} \] Substituting the value of ω: \[ f = \frac{2\pi \left( \frac{1}{0.04} \right)}{2\pi} = \frac{1}{0.04} = 25 \text{ Hz} \] ### Step 3: Find the maximum acceleration (a_max) The maximum acceleration for a wave can be calculated using the formula: \[ a_{max} = A \omega^2 \] Where: - \( A = 3 \) cm (which we convert to meters: \( A = 0.03 \) m), - \( \omega = 2\pi \left( \frac{1}{0.04} \right) \). Now, calculate ω: \[ \omega = \frac{2\pi}{0.04} = 50\pi \text{ rad/s} \] Now, substituting these values into the acceleration formula: \[ a_{max} = 0.03 \times (50\pi)^2 \] \[ a_{max} = 0.03 \times 2500\pi^2 \] \[ a_{max} = 75\pi^2 \text{ m/s}^2 \] ### Step 4: Approximate π² Using \( \pi^2 \approx 10 \): \[ a_{max} \approx 75 \times 10 = 750 \text{ m/s}^2 \] ### Final Results - Frequency \( f = 25 \text{ Hz} \) - Maximum Acceleration \( a_{max} \approx 750 \text{ m/s}^2 \) ### Summary The frequency of the wave is \( 25 \text{ Hz} \) and the maximum acceleration is approximately \( 750 \text{ m/s}^2 \). ---

To solve the problem, we need to extract the frequency of the wave and the maximum acceleration from the given wave equation: **Given Wave Equation:** \[ y = 3 \sin \left( 2\pi \left( \frac{t}{0.04} - \frac{x}{0.01} \right) \right) \] ### Step 1: Identify the angular frequency (ω) The general form of a wave equation is: \[ y = A \sin(\omega t - kx) \] ...
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