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Two small loudspeakers A , B ( 1m apart)...

Two small loudspeakers `A , B` ( `1m` apart) are connected to the same oscillator so that both emit sound waves of frequency `1700 Hz` in phase . `A` sensitive detector , detects a maximum wave at `P` on the perpendicular bisector `MP of AB` and another maximum wave when it first reaches a point `Q` directly opposite to `B`. Calculate the speed `c` of the sound waves in air .

Text Solution

Verified by Experts

`AQ - BQ = lambda` for reinforcement of waves at `Q`
or ` sqrt( 1.00^(2) + 2.40^(2)) - 2.40 = lambda or lambda = 0.20 m`
`because c = n lambda rArr c = 1700 xx 0.2 = 340 m//s`
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