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Sound waves from a tuning fork placed at a point `P` reach another point `Q` , by two separate paths `PRQ and PSQ` . When `PSQ` is greater than `PRQ by 11.5 cm` , there is silence at `Q` . When the difference is `23 cm` , the sound becomes loudest at `Q`, and when `34.5 cm` , there is silence , and so on . Explain this effect and calculate the frequency of the fork if the velocity of sound is taken to be `331.2 m//s`.

Text Solution

Verified by Experts

Path difference from one minimum to the next minimum is `lambda`. Here path difference from one minimum to the next minimum is `23.0 cm . lambda =23.0 cm = 0.23 m`.
` C = n lambda`
or ` n = ( 331.2)/(0.23) = 1440 Hz`
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