An open organ pipe has a fundamental frequency of `300 Hz` . The first overtone of a closed organ pipe has the same frequency as the first overtone of the open pipe . Find length of each pipe . The velocity of sound in air ` = 350 m//s`.

Explanation

For open pipe :
` f_(1) = 300 = (v)/( 2l_(1)) rArr l_(1) = (v)/( 600) = (350)/(600) = 0.58 m`
For closed pipe : `( 3v)/( 4 l_(2)) = 2 f_(1)`
`rArr ( 3v)/( 4 l_(2)) = 600 rArr l_(2) = 0.44 m`