A string of length `25 cm` is stretched by a load of `10 kg`. What is the highest overtone that a man of normal hearing capacity can detect ? The mass of the string is

Explanation

` f = (1)/(2 l) sqrt((T)/(m)) = (1)/( 2 xx 0.25) sqrt(( 10 xx 9.8)/(0.5 xx 10^(-3)) xx (1)/(0.25)) = 1770.8 Hz`
A string emits the full series of harmonics . The highest frequency that a man of normal hearing can detect is `20 , 000 Hz` . Let `n` be the highest harmonic that can be detected by a man of normal hearing . Then
` n xx 1770.8 = 20000 or n = 11.29`
`:. "Acceptable value" = 11`
`:. "Highest overtone" = 11 - 1 = 10`