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Two tuning forks A and B give 4 beats//...

Two tuning forks `A and B` give ` 4 beats//s` when sounded together . The frequency of `A is 320 Hz`. When some wax is added to `B` and it is sounded with `A , 4 beats//s per second` are again heard . The frequency of `B` is

A

`312 Hz`

B

`316 Hz`

C

`324 Hz`

D

`328 Hz`

Text Solution

Verified by Experts

The correct Answer is:
C
Since there is no change in beats . Therefore the original frequency of `B` is
` n_(2) = n_(1) + x = 320 + 4 = 324`
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