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Two identical sound S1 and S2 reach at a...

Two identical sound `S_1` and `S_2` reach at a point P is phase. The resultant loudness at point P is `n` dB higher than the loudness of `S_1` the value of n is :

A

` 2`

B

`4`

C

`5`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
D
Let `a` be the amplitude due to `S_(1) and S_(2)` individually .
Intensity due to `S_(1) = I_(1) = Ka^(2) `
Intensity due to ` S_(1) + S_(2) = I = K( 2a)^(2)`
`= 4 I_(1)`
`:. N = 10 log_(10) ((4 l_(1))/(I_(1)))`
` = 10 log _(10) (4) = 6`
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