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A sound wave of wavelength 0.40 m enter...

A sound wave of wavelength `0.40 m` enters the tube at `S`. The smallest radius `r` of the circular segment to hear minimum at detector `D` must be

A

`1.75 m`

B

`0.175 m`

C

`0.93 m`

D

`9.3 m`

Text Solution

Verified by Experts

The correct Answer is:
B
Path difference ` = ( pi r - 2 r)`
` = ( 2 n - 1) lambda//2 ` for minima
Given `lambda = 0.40 m` , for smallest radius ` n = 1 (3.14 - 2) r = lambda//2`
`r = (lambda)/( 2 xx 1.14) = (0.40)/( 2 xx 1.14) = 0.175 m`
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