A sound wave of frequency `440 Hz` is passing through in air. An `O_(2)` molecule `( mass = 5.3 xx 10^(- 26) kg)` is set in oscillation with an amplitude of `10 ^(-6) m`. Its speed at the centre of its oscillation is

Options

A. `1.70 xx 10^(-5) m//s`
B. `17.0 xx 10^(-5) m//s`
C. `2.76 xx 10^(-3) m//s`
D. `2.77 xx 10^(-5) m//s`

Answer

C

Explanation

`v_(max) = omega_(n) A = ( 2 pi f) A = ( 2 pi) = (2 pi) (440) (10^(-6))`
` = 2.76 xx 10^(-3) m//s`