Home
Class 11
PHYSICS
A travelling wave y = A sin (k x - omeg...

A travelling wave ` y = A sin (k x - omega t + theta)` passes from a heavier string to a lighter string . The juction of the strings is at ` x = 0`. The equation of the reflected wave is

A

`y' = 0.5 A sin ( kx + omega t + theta)`

B

`y' = - 0.5 A sin ( kx + omega t + theta)`

C

`y' = - 0.5 A sin ( kx - omega t - theta)`

D

`y' = - 0.5 A sin ( kx + omega t - theta)`

Text Solution

Verified by Experts

The correct Answer is:
A
As wave has been reflected from a rare medium , therefore there is no change in phase , but starts travelling in `- x` direction .
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SUPERPOSITION AND STANDING WAVES

    CENGAGE PHYSICS|Exercise Multiple|26 Videos

  • SUPERPOSITION AND STANDING WAVES

    CENGAGE PHYSICS|Exercise Assertion - Reasoning|6 Videos

  • SUPERPOSITION AND STANDING WAVES

    CENGAGE PHYSICS|Exercise Subjective|24 Videos

  • SOUND WAVES AND DOPPLER EFFECT

    CENGAGE PHYSICS|Exercise Integer|16 Videos

  • THERMODYNAMICS

    CENGAGE PHYSICS|Exercise 24|1 Videos

Similar Questions

Explore conceptually related problems

Equation of travelling wave on string

transverse simple harmonic wave is travelling on a string. The equation of the wave:

Knowledge Check

  • A travelling wave y=A sin (kx- omega t +theta ) passes from a heavier string to a lighter string. The reflected wave has amplitude 0.5A . The junction of the strings is at x=0 . The equation fo the refelcted wave is :

    A
    `y'=0.5 A sin (kx+omegat+theta)`
    B
    `y'=-0.5 A sin (kx+omegat + theta )`
    C
    `y'=-0.5 A sin ( omega t -kx - theta )`
    D
    `y'=0.5 A sin (kx+omega t -theta)`

  • A wave travels on a light string. The equation of the waves is y= A sin (kx - omegat + 30^@) . It is reflected from a heavy string tied to an end of the light string at x = 0. If 64% of the incident energy is reflected, then the equation of the reflected wave is

    A
    `y = 0.8 A sin (kx - omegat + 30^@ + 180^@)`
    B
    `y = 0.8 A sin (kx + omegat + 30^@ + 180^@)`
    C
    `y= 0.8 A sin (kx - omegat - 30^@)`
    D
    `y= 0.8 A sin (kx - omegat + 30^@)`

  • A wave travels on a light string. The equation of the wave is Y = A sin (kx - omegat + 30^(@)) . It is relected from a heavy string tied to an end of the light string at x = 0 . If 64% of the incident energy is reflected the equation of the reflected wave is

    A
    `Y = 0.8 A sin (kx - omegat + 30^(@) + 180^(@))`
    B
    `Y = 0.8 A sin (kx + omegat + 30^(@) + 180^(@))`
    C
    `Y = 0.8 A sin (kx + omegat - 30^(@))`
    D
    `Y = 0.8 A sin (kx + omegat + 30^(@))`

    • Similar Questions

    Explore conceptually related problems

    A composite string is made up by joining two strings of different masses per unit length rightarrow mu and 4mu the composite string is under the same tension A transverse wave pulse Y=(6mm) sin (5t+40x) where is in seconds and x in metres is sent along the lighter string towards the joint the joint is at x=0 the equation of the wave pulse reflected from the joint is

    A sinusoidal transverse wave is traveling on a string. Any point on the string

    A wave y = a sin (omegat - kx) on a string meets with another wave producing a node at x = 0 . Then the equation of the unknown wave is

    The equation of a wave travelling on a string is d

    The equation of a wave travelling on a stretched string along the x-axis is y = ae^(-(bx+ct)) . The direction of propagation of wave is

    Home
    Profile