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A tube of a certain diameter and of leng...

A tube of a certain diameter and of length `48cm` is open at both ends. Its fundamental frequency is found to be `320 Hz`. The velocity of sound in air is `320 m//sec`. Estimate the diameter of the tube.
One end of the tube is now closed. Calculate the lowest frequency of resonance for the tube.

A

`163.27 Hz`

B

`205.37 Hz`

C

`153.93 Hz`

D

`198.88 Hz`

Text Solution

Verified by Experts

The correct Answer is:
A
If one end is closed , the effective length of the tube will be :
`l' = l + e `
`f = ( c )/( 4 l') = ( c) /(4 ( l' + e))`
`v = (320 xx 100)/( 4( 48 + 0.3 xx 3.33))`
`= (32000)/(4 xx 49) = 163.27 Hz`
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