A student is performing the experiment of resonance column. The diameter of the column tube is `4cm`. The frequency of the tuning fork is `512 Hz`. The air tempreture is `38@C` in which the speed of sound is `336 m//s`. The zero of the meter scale coincide with the top end of the resonance column tube. when the first resonance ocuurs, the reading of the water level in the column is

Options

A. 14.0 cm
B. 15.2 cm
C. 16.4 cm
D. 17.6 cm

Answer

B

Explanation

`(V)/(4(l+e)) =f`
`rArr l +e = (V)/(4f)`
`rArr l = (V)/(4f) -e`
Here `e =(0.6)r = (0.6)(2) = 1.2 cm`
So `l = (336 xx 10^(2))/(4 xx 512) -1.2 = 15.2 cm`.