The shape of a moleculs is determined by electron pair repulsions in the valence shell A.lp occupies a larger space than a bp because it is not shared by two nuclei The the lp lp repulsion is greater than the lp-lp repulsion, which in trun is greater the lp-lp repulsion. The presence of lp causes distortion of bond angles hence, a daviation from an ideal shape THe extent of distortion depends upon the orientation of the lp's around the central atom In a trigonal bipyramid, the lp's occupy equatorial positions than the apical ones In `AB_(n)` type molecules, as the `EN` of A increases, the bp's come closer and the repulsion between them increases. On the other hand, as `EN` of `B` increases, the lp s get farther and repulsion decreases
Which of the following statements is true ?

Options

A. `F-N-F` angle in `NF_(3)` is greater than `H-N-H` angle in `NH_(3)` .
B. `F-N-F` angle in `NF_(3)` is smaller than `H-N-H` angle in `NH_(3)` .
C. `H-O-H` angle in `H_(2)O` is greater than `H-N-H` angle in `NH_(3)` .
D. `F -O-F` angle in `F_(2)O` is greater than `H-O-H` angle in `H_(2)O` ..

Answer

B

Explanation

Sameexplanation in solution of Question 1 above `EN` of `F gt EN` of `H` Hence bond angle of `NH_(3) gt NF_(3)` or `NH_(3) gt NF_(3)` .