Which of the following are true ?.

Options

A. `SH_(6)` and `BiCI_(5)` do not exist
B. There are two `ppi-dpi` bond is `SO_(3)`
C. `SeF_(4)` and `CH_(4)` are tetrahedral ion
D. `I_(3)^(Θ)` is a linear molecule with `sp^(3)` d hybridisation

Answer

A, B, D

Explanation

`SH_(6)` and `BiCI_(5)` do not exist In `SH_(6),EN` of H-atom is not sufficient to excite `e^(-') s` from 3p orbital to 3d orbitals from S-atom In `BiCI_(5) Bi^(3+)` is more stable `Bi^(5+)` due to inert pair effect
(b) p(pi -ppi) bond =1 (ppi -ppi) bond =2
(c ) Wrong Hybridisation of `:Se F_(4) implies (1)/(2) (6 +4) =5 = sp^(3) d`
Geometry =Tbp Due to one lp of `e^(-')s` its shape is see-saw
Hybridisation of `CH_(4) implies sp^(3)` and `TH`
(d) Correct Hybridisation of `I_(3)^(Θ) II_(2) = (1)/(2) (7 + 2 +1)`
`= 5 = sp^(3) d` Due to three lp of `e^(-')s` it is linear .