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In PO(4)^(3-),P-O bond order is ....

In `PO_(4)^(3-),P-O` bond order is .

A

`1.25`

B

`2`

C

`-0.75`

D

`-3`

Text Solution

Verified by Experts

The correct Answer is:
A
`P-O` bond order = Total number of bonds//Total number of resonating structures
` = (5)/(4) = 1.25`
.
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