The hybridization of atomic orbitals of nitrogen is `NO_(2)^(+), NO_(3)^(-)`, and `NH_(4)^(+)` respectively are

Options

A. `sp,sp^(3)` and `sp^(2)`, respectively
B. `sp,sp^(2)` and `sp^(3)`, respectively
C. `sp^(2) ,sp ` and `sp^(3)`, respectively
D. `sp,sp^(2), sp^(3)` and sp,respectively

Answer

B

Explanation

Hybridisation
(1) `NO_(2)^(o+) rArr (1)/(2) (5 +0-1) =2 =sp`
(2) `NO_(3)^(Theta) rArr (1)/(2) (5 +0 +1) =3 =sp^(2)`
(3) `NH_(4)^(o+) rArr (1)/(2) (5 +4 -1) =4 = sp^(3)` .