The correct order of hybridisation of the central atom in the following species ` NH_3 ,[PtCl_4 ]^(2-) , PCl_5` and ` BCl_3` is :

Options

A. `dsp^(2), dsp^(3), sp^(2)` and `sp^(3)`
B. `sp^(3), dsp^(3), sp^(3) d` and `sp^(2)`
C. `dsp^(2), dsp^(2), sp^(3)` and `dsp^(3)`
D. `dsp^(2), sp^(3), sp^(2)` and `dsp^(3)`

Answer

B

Explanation

`overset(..)NH_(3) rArr (1)/(2) (5 +3) =4= sp^(3)`
(2) `[Pt CI_(4)]^(2-) hArr` coordination number `(CN) =4`
Hence it is d `sp^(2)` hybridisedv
(3) `PCI_(5) rArr (1)/(5) (5 +5) = 5 =sp^(3)d`
(4) `BCI_(3) rArr (1)/(2) (3 =3) = 3 = sp^(2)` .