`20mL` of `H_2O_2` is reacted completely with acidified `K_2Cr_2O_7` solution. `40mL` of `K_2Cr_2O_7` solution is required to oxidise the `H_2O_2` completely. Also, `2.0mL` of the same `K_2Cr_2O_7` solution is required to oxidise `5.0mL` of a `1.0MH_2C_2O_4` solution to reach equivalence point. Which of the following statements is`//`are correct?

Options

A. The `H_(2)O_(2)` solution is `5M`
B. The volume strength of `H_(2)O_(2)` is `56 V`
C. The volume strength of `H_(2)O_(2)` is `112 V`
D. If `40 mL` more `5M//8H_(2)O` is further added to the `10 mL` more `H_(2)O_(2)` solution, the volume strength of the resulting solution is changed to `16.8 V`

Answer

A, B, D

Explanation

`(i) mEq H_(2)O_(2)=mEq of Cr_(2)O_(7)^(2-)`
`20 mLxxN_(1)=40mLxxN_(2)...(i)`
`2.0xxN_(2)-=5.0xx1.0xx2`
`N_(2)(Cr_(2)O_(7)^(2-))=5....(ii)`
Substituting the value of `N_(2)` from `(ii)` in `(i)`
`20 mLxxN_(1)=40 mLxx5`
`N_(1)(H_(2)O_(2))=10 N`
`M_(1)(H_(2)O_(2))=10/2=5 M`
b. `1NH_(2)O_(2)=5.6 V`
`:. 10 N H_(2)O_(2)=56 V`
c. `N_(1)V_(1)+N_(2)V_(2)=N_(3)V_(3)(V_(3)=10+40=500 mL)`
`10xx10+40xx5/8xx2=N_(3)xx50`
`N_(3)(H_(2)O_(2))=3N`
The volume strength of `H_(2)O_(2) =5.6xx3=16.8 V`