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H2O2 is reduced by...

`H_2O_2` is reduced by

A

`O_(3)`

B

acidic `KMnO_(4)` solution

C

lead sulphide suspension in water

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
`PbS+4H_(2)O_(2)toPbSO_(4)+4H_(2)O`
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Speed of decomposition of H_(2)O_(2) is reduced by :

Decomposition of H_2O_2 was studied by a titration against KMnO_4 solution. It was found that 0.4 mole of H_2O_2 was reduced to 0.2 mole in 20 minutes and to 0.1 mole in 40 minutes and to 0.05 mole after one hour. The order of reaction will be :

H_2O_2 is reduced rapidly by Sn^(2+). H_2O_2 is decomposed slowly at room temperature to yeild O_2 and H_2O_2 . 136g of 10% by mass of H_2O_2 in water is treated with 100mL of 3M Sn^(2+) and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are: 2H^(o+)+H_(2)O_(2)+Sn^(2+)toSn^(4+)+2H_(2) 2H_(2)O_(2)to2H_(2)O+O_(2) The equivalent of H_2O_2 reacted with Sn^(2+) is

H_2O_2 is reduced rapidly by Sn^(2+). H_2O_2 is decomposed slowly at room temperature to yeild O_2 and H_2O_2 . 136g of 10% by mass of H_2O_2 in water is treated with 100mL of 3M Sn^(2+) and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are: 2H^(o+)+H_(2)O_(2)+Sn^(2+)toSn^(4+)+2H_(2) 2H_(2)O_(2)to2H_(2)O+O_(2) Calculate the volume of O_2 produced at 27^@C and 1 atm after H_2O_2 is reacted with Sn^(2+) and the mixture is allowed to stand.

H_2O_2 is reduced rapidly by Sn^(2+). H_2O_2 is decomposed slowly at room temperature to yeild O_2 and H_2O_2 . 136g of 10% by mass of H_2O_2 in water is treated with 100mL of 3M Sn^(2+) and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are: 2H^(o+)+H_(2)O_(2)+Sn^(2+)toSn^(4+)+2H_(2) 2H_(2)O_(2)to2H_(2)O+O_(2) The equivalent of H_2O_2 left after reacting with Sn^(2+) is

H_2O_2 is reduced rapidly by Sn^(2+). H_2O_2 is decomposed slowly at room temperature to yeild O_2 and H_2O_2 . 136g of 10% by mass of H_2O_2 in water is treated with 100mL of 3M Sn^(2+) and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are: 2H^(o+)+H_(2)O_(2)+Sn^(2+)toSn^(4+)+2H_(2) 2H_(2)O_(2)to2H_(2)O+O_(2) The volume strength of H_2O_2 left after reacting with Sn^(2+)

[A]: Oxidation of H_2O takes place during pho- tosynthesis. [R]: Photosynthesis is an oxidation-reduction process where H_2O is oxidised to O_2 and CO_2 is reduced to (CH_2O)_(n) ·

CENGAGE CHEMISTRY-HYDROGEN, WATER AND HYDROGEN PEROXIDE-Exercises (Single Correct)
  1. H2O2 cannot act as

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  2. Hardness of water is due to dissolved impurities of

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  3. H2O2 is reduced by

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  4. When water is dropped over sodium peroxide, the colourless gas produce...

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  5. In which of the following reaction dihydron acts as an oxidising agent...

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  6. Which of the following metal does not produce dihydrogen gas with dilu...

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  7. Which oxide cannot be reduced by H2?

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  8. Ortho- and para-hydrogen differ in

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  9. Nascent hydrogen consists of

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  10. 30-volume hydrogen peroxide means

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  11. The compound which gives H2O2 on treatment with dilute acid is

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  12. When a sample of hard water is passed through the layer of sodium zeol...

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  13. Hydrolysis of one mole of peroxodisulphuric acid produces acid produce...

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  14. Barium peroxide reacts with phosphoric acid to produce barium phosphat...

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  15. One part of heavy water is present in X parts of ordinary water. Here ...

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  16. The hydride ion H^(ɵ) is a stronger base than hydroxide ion. Which of ...

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  17. The volume strength of 1*5 N H(2)O(2) solution is

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  18. Which of the following pair of substances will not evolve H2 gas

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  19. H2 molecule has two electrons and two nuclei. In which form of hydroge...

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  20. What is false about Lane's process?

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