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The volume of 10 volume of H2O2 required...

The volume of `10` volume of `H_2O_2` required to liberate `500mL` of `O_2` at `STP is

A

`25 mL`

B

`50 mL`

C

`100 mL`

D

`125 mL`

Text Solution

Verified by Experts

The correct Answer is:
B
`10` volume `H_(2)O_(2)` means 10 mL of `O_(2)` is produced at `STP` from `1` mL of 10vol `H_(2)O_(2)`
Hence `500` mL of `O_(2)` is produce at `STP` from
`500/10=50` mL of 10 vol `H_(2)O_(2)`
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