If `100 mL` of acidified `2NH_(2)O_(2)` is allowed to react with `KMnO_(4)` solution till there is light tinge of purples colour, the volume of oxygen produced at `STP` is :

Options

A. `2.24 L`
B. `1.12 L`
C. `3.36 L`
D. `4.48 L`

Answer

A

Explanation

Volume of `O_(2)` at `STP`
`=100mLxx11.2mL` volume strength
`=1120 mL` of `O_(2)at STP`
Since `1N=5.6` volume strength of `H_(2)O_(2)`
`2N=11.2` volume strength of `H_(2)O_(2)`
Volume of `O_(2)` produced by `H_(2)O_(2)=1120 mL`
Same volume of `O_(2)` will be produced by `KMnO_(4)`, i.e., `1120 mL`