The purity of `H_2O_2` in a given sample is `85%.` Calculate the weight of impure sample of `H_2O_2` which requires `10mL` of `M//5 KMnO_4` solution in a titration in acidic medium

Options

A. `2 g`
B. `0.2 g`
C. `0.17 g`
D. `0.15 g`

Answer

B

Explanation

`mEq of MnO_(4)^(ɵ)-=mEq of H_(2)O_(2)`
`10xxM/5xx5-=mEq of H_(2)O_(2)`
`implies 10 mEq -=mEq of H_(2)O_(2)`
Weight of `H_(2)O_(2)=10xx10^(-3)xx34/2xx0.17=0.2 g`
Weight of impure `H_(2)O_(2)=100/85xx0.17=0.2 g`