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The pair of compounds which cannot exist...

The pair of compounds which cannot exist together in aqueous solution is:
`(I) NaH_(2)PO_(4)` and `NaHCO_(3)" "(II) Na_(2)CO_(3)` and `NaHCO_(3)`
`(III) NaOH` and `NaH_(2)PO_(2)" "(IV) NaHCO_(3)` and `NaOH`

A

`NaH_(2)PO_(4)` and `Na_(2)HPO_(4)`

B

`Na_(2)CO_(3)` and `NaHCO_(3)`

C

`NaOH` and `NaH_(2)PO_(4)`

D

`NaHCO_(3)` and `NaOH`

Text Solution

Verified by Experts

The correct Answer is:
C, D
NaOH is a strong base whereas `NaH_(2)PO_(4)` is a salt of strong base (NaOH) and `H_(3)PO_(4)` (weak acid). Hence, NaOH and `NaH_(2)PO_(4)` do not exist together in aqueous solution. NoOH is a strong base, whereas `NaHCO_(3)` is a salt of stronge base `(NaOH)` and weak acid `(H_(2)CO_(3))`. Hence NaOH and `Na_(2)CO_(3)` do not exist together.
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The pairs of compounds which cannot exist together in aquous solution are: (I) NaH_(2)PO_(4) and Na_(2)HCO_(3) (II) Na_(2)CO_(3) and NaOH (III) NaOH and NaH_(2)PO_(4) (IV) NaHCO_(3) and NaOH

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