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Calculate heat of solution of NaCI form ...

Calculate heat of solution of NaCI form the following data:
Hydration energy of `Na^(o+)= - 389 kJ mol^(-1)`
Hydration energy of `CI^(Θ)= - 382 kJ mol^(-1)`
Lattic energy of `NaCI= - 776 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
`(5)`
Hydration energy of NaCI = Hydration energy of `Na^(o+)`
+ Hydration energy of `CI^(Θ)`
`= -389 kJ mol^(-1) - 382 kJ mol^(-1)`
`= -771 kJ mol^(-1)`
Heat of solution `(Delta` soln `H^(Θ))`
= Hydration energy - lattice energy
`= [-771-(-776)]kJ mol^(-1)`
`= 5 kJ mol^(-1)`
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