A solution of sodium sulphate in qater is electrolysed using inert electrodes, The products at the cathode and anode are respectively.

Options

A. `H_(2),O_(2)`
B. `O_(2),H_(2)`
C. `O_(2),Na`
D. `O_(2),SO_(3)`

Answer

A

Explanation

In aqueous solution: reducton potential of `H_(2)Ogt` reduction potential `Na^(o+)` .
Hence, `H_(2)O` undergoes reaction at cathode to give `H_(2(g))`
`H_(2)O+e^(-)rarr(1)/(2)H_(2(g))+overset(Θ)OH_((aq))`
Similary, oxidation potential of `H_(2)Ogt` oxidation potential of `SO_(4)^(2-)` ions.
Hence, oxidation of `H_(2)O` occurs at anode to give `O_(2(g))`
`H_(2)Orarr 2H^(o+)+(1)/(2)O_(2(g))+2e^(-)`