Boron nitride is isoelectronic with

Options

A. `C_(2)`
B. `B_(2)`
C. `N_(2)`
D. `O_(2)`

Explanation

To determine which species is isoelectronic with boron nitride (BN), we first need to calculate the total number of electrons in boron nitride.

### Step-by-Step Solution:

1. **Identify the Atomic Numbers of Boron and Nitrogen:**
- Boron (B) has an atomic number of 5, which means it has 5 electrons.
- Nitrogen (N) has an atomic number of 7, which means it has 7 electrons.

2. **Calculate the Total Number of Electrons in Boron Nitride:**
- The total number of electrons in boron nitride (BN) is the sum of the electrons from boron and nitrogen:
\[ \text{Total electrons in BN} = \text{Electrons from B} + \text{Electrons from N} = 5 + 7 = 12 \]

3. **Identify the Options to Compare:**
- We need to find a molecule or ion that also has a total of 12 electrons.

4. **Check the Options:**
- **C2 (Diatomic Carbon):**
- Each carbon atom has 6 electrons, so for C2:
\[ \text{Total electrons in C2} = 6 + 6 = 12 \]
- **B2 (Diatomic Boron):**
- Each boron atom has 5 electrons, so for B2:
\[ \text{Total electrons in B2} = 5 + 5 = 10 \]
- **N2 (Diatomic Nitrogen):**
- Each nitrogen atom has 7 electrons, so for N2:
\[ \text{Total electrons in N2} = 7 + 7 = 14 \]
- **O2 (Diatomic Oxygen):**
- Each oxygen atom has 8 electrons, so for O2:
\[ \text{Total electrons in O2} = 8 + 8 = 16 \]

5. **Conclusion:**
- The only species that has the same number of electrons (12) as boron nitride (BN) is C2.
- Therefore, boron nitride is isoelectronic with C2.

### Final Answer:
Boron nitride (BN) is isoelectronic with C2 (Diatomic Carbon).