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Prove that, in a right-angled triangle, ...

Prove that, in a right-angled triangle, the square of hypotenuse is equal to the sum of the square of remaining two sides.

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In order to prove, 'In a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of remaining two sides (i) Draw a near labelled figure. (ii) Write 'Given' and 'To Prove' from the figure drawn by you.

(Pythagoras's Theorem) Prove by vector method that in a right angled triangle,the square of the hypotenuse is equal to the sum of the squares of the other two sides.

(Pythagorass Theorem) Prove by vector method that in a right angled triangle,the square of the hypotenuse is equal to the sum of the squares of the other two sides.

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Prove that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. Use the above theorem, in the following. If ABC is an equilateral triangle with AD bot BC , then prove that AD^(2) = 3DC^(2) .

STATEMENT In a right triangle the square of the hypotenuse equals the sum of the squares of its remaining two sides.

Prove that, in a right triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides. Using the above, do the following: Prove that, in a DeltaABC , if AD is perpendicular to BC, dien AB^(2) + CD^(2) = AC^(2) + BD^(2) .

PYTHAGORAS THEOREM : In a Right angled triangle; the square of hypotenuse is equal to the sum of the squares of the other two sides.

In a right-angled triangle,the square of hypotenuse is equal to the sum of the squares of the two sides.Given that /_B of /_ABC is an acute angle and AD perp BC .Prove that AC^(2)=AB^(2)+BC^(2)-2BC.BD

Theorem 6.8 : In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.