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Let log2N=a1+b1,log3N=a2+b2 and log5N=a3...

Let `log_2N=a_1+b_1,log_3N=a_2+b_2` and `log_5N=a_3+b_3`, where `a_1,a_2,a_3notin1` and `b_1,b_2 b_3notin [0,1)`.
If `a_1=6,a_2=4` and `a_3=3`,the difference of largest and smallest integral values of N, is

A

2

B

8

C

14

D

20

Text Solution

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The correct Answer is:
A
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