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If A and B are two events such that P(A)...

If A and B are two events such that `P(A)gt0 and P(B)!=1,` then `P((overline(A))/(B))` is equal to

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To solve the problem, we need to find \( P(\overline{A} | B) \), which is the probability of the complement of event A given event B. ### Step-by-Step Solution: 1. **Understanding the Conditional Probability**: The conditional probability \( P(\overline{A} | B) \) can be expressed using the formula: \[ P(\overline{A} | B) = \frac{P(\overline{A} \cap B)}{P(B)} \] 2. **Using the Complement Rule**: We know that the probability of an event and its complement sum up to 1. Therefore, we can express \( P(A) \) in terms of \( P(\overline{A}) \): \[ P(A) + P(\overline{A}) = 1 \implies P(\overline{A}) = 1 - P(A) \] 3. **Finding \( P(\overline{A} \cap B) \)**: To find \( P(\overline{A} \cap B) \), we can use the law of total probability: \[ P(\overline{A} \cap B) = P(B) - P(A \cap B) \] However, we can also express \( P(A \cap B) \) in terms of conditional probability: \[ P(A \cap B) = P(A | B) \cdot P(B) \] 4. **Substituting Back**: Now, substituting \( P(A \cap B) \) back into our equation for \( P(\overline{A} \cap B) \): \[ P(\overline{A} \cap B) = P(B) - P(A | B) \cdot P(B) \] This simplifies to: \[ P(\overline{A} \cap B) = P(B)(1 - P(A | B)) \] 5. **Final Calculation**: Now we can substitute this into our conditional probability formula: \[ P(\overline{A} | B) = \frac{P(\overline{A} \cap B)}{P(B)} = \frac{P(B)(1 - P(A | B))}{P(B)} \] Since \( P(B) \neq 0 \), we can cancel \( P(B) \): \[ P(\overline{A} | B) = 1 - P(A | B) \] ### Conclusion: Thus, the final result is: \[ P(\overline{A} | B) = 1 - P(A | B) \]
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