Home
Class 12
MATHS
There are n different objects 1, 2, 3, ...

There are n different objects 1, 2, 3, …, n distributed at random in n places marked 1, 2, 3,…, n. If p be the probability that atleast three of the object occupy places corresponding to their number, then the value of 6p is

Text Solution

Verified by Experts

The correct Answer is:
`(1)`
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY

    ARIHANT MATHS|Exercise Exercise (Statement I And Ii Type Questions)|12 Videos
  • PROBABILITY

    ARIHANT MATHS|Exercise Exercise (Subjective Type Questions)|15 Videos
  • PROBABILITY

    ARIHANT MATHS|Exercise Exercise (Passage Based Questions)|27 Videos
  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|28 Videos
  • PRODUCT OF VECTORS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|52 Videos

Similar Questions

Explore conceptually related problems

Four different objects 1,2,3,4 are distributed at random on four places marked 1,2,3,4 . What is the probability that none of the objects occupies the place corresponding to its number?

There are 10 different objects 1,2,3…10 arranged at random in 10 planes marked, 1,,2,3,….10. The probability that exactly five of these objects occupy places corresponding to their number is

Five different objects A_(1),A_(2),A_(3),A_(4),A_(5) are distributed randomly in 5 places marked 1,23,4,5. One arrangement is picked at random. The probability that in the selected arrangement,none of the object occupies the place corresponding to its number,is

If (p/q)^(n-1)=(q/p)^(n-3) , then the value of n is

Out of 2n tickets numbered 1,2,......,2n three are chosen at random.The probability that the numbers on them are in A.P.is

There are n+ 3(n > 1) seats numbered 1, 2, 3, , n + 3. There are also n+ 3 persons who are holding tickets numbered 1, 2, 3, . . . , n + 3. They take seats at random. Find the probability that exactly three persons take seats having the same numbers as that in their tickets.

n letters are written to n different persons and addresses on the n envelopes are also written. If the letters are placed in the envelopes at random,the probability that at least one letter is not placed in the right envelope,is (A) 1-(1)/(n) (B) 1-(1)/(2n) (C) 1-(1)/(n^(2))(D)1-(1)/(n!)

The probability of ‘n’ independent events are P_(1) , P_(2) , P_(3) ……., P_(n) . Find an expression for probability that at least one of the events will happen.