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Let `E^c` denote the complement of an event `E.` Let `E,F,G` be pairwise independent events with `P(G) gt 0` and `P(E nn F nn G)=0` Then `P(E^c nn F^c nn G)` equals (A) `P(E^c)+P(F^c)` (B) `P(E^c)-P(F^c)` (C) `P(E^c)-P(F)` (D) `P(E)-P(F^c)`

A

`P(E^c)+P(F^c)`

B

`P(E^c)-P(F^c)`

C

`P(E^c)-P(F)`

D

`P€-P(F^c)`

Text Solution

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The correct Answer is:
C
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