At high temperature, carbon reacts with water to produce a mixture of `CO` and `H_(2)`.
`C + H_(2) O overset ("Heat heat")rarr CO + H_(2)`
`CO` is separated from `H_(2)` and then used to separate `Ni` from `CO` by forming a volatile compound, nickel tetracarbonyl `(Ni(CO)_(4))`.
`Ni + 4CO rarr Ni(CO)_(4)`
(a) Formation of volatile `Ni(CO)_(4)` and its subsequent heating give pure `Ni`. Name the process involved.
(b) How many moles of `Ni(CO)_(4)` could be obtained from `CO` produced by the reaction of `75.0 g` is carbon ?

Explanation

(a) Mond's process
(b)`{:(C,+,H_(2)O,rarr,CO,+,H_(2)),(12g,,18g,,12+16,,2g),(,,,,=28g,,):}`
`12 g` of `C` reacts to produce `28 g` of `CO`
`75 g` of `C` will react to produce
`(28)/(12) xx 75 g of CO = 175 g of CO = (175)/(28) mol of CO`
=`6.25` moles of `CO`
`Ni + 4CO rarr Ni(CO)_(4)`
Since `4 mol` of `CO` produces `1 mol` of `Ni(CO)_(4)`.
`6.25 mol` of `CO` will produce
`(1)/(4) xx 6.25 mol of Ni(CO)_(4) = 1.5625 mol of Ni(CO)_(4)`
Hence, `1.5625 mol` of `Ni(CO)_(4)` could be obtained from `CO` produced by the reaction of `75.0 g` of carbon.