Home
Class 12
CHEMISTRY
Chief ore of Zn is ZnS. The ore is conce...

Chief ore of `Zn` is `ZnS`. The ore is concentrated by froth flotation process and then heated in air to convert `ZnS` to `ZnO`. ltntgt `2 ZnS + 3O_(2) rarr 2 ZnO + 2 SO_(2)`…(i)
`ZnO`, thus formed is treated with dilute `H_(2) SO_(4)`.
`ZnO + H_(2) SO_(4) rarr ZnSO_(4) + H_(2) O` ....(ii)
On electrolysis of `ZnSO_(4(aq)), Zn` metal is produced.
`2 ZnSO_(4) + H_(2) O rarr 2 Zn + 2H_(2) SO_(4) + O_(2)`....(iii)
What mass of `Zn` will be obtained from an ore containing `225 kg` of `ZnS` ? `(Zn = 65, S = 32, O = 16, H = 1)`.

A

102 kg

B

151 kg

C

112 kg

D

134 kg

Text Solution

Verified by Experts

The correct Answer is:
B

`225 xx 10^(3) of ZnS = (225 xx 10^(3))/(97)`
=`2.32 xx 10^(3) mol ZnS`
=`2.32 xx 10^(3) mol of Zn`
=`2.32 xx 10^(3) xx 65 of Zn`
=`150.8 Kg Zn ~~ 151 Kg Zn`.
Promotional Banner

Topper's Solved these Questions

  • GENERAL PRINCIPLES AND PROCESS OF ISOLATION OF ELEMENTS

    CENGAGE CHEMISTRY|Exercise Exercise (Multiple Correct)|43 Videos
  • GENERAL PRINCIPLES AND PROCESS OF ISOLATION OF ELEMENTS

    CENGAGE CHEMISTRY|Exercise Exercise (Single Correcttype)|106 Videos
  • GENERAL PRINCIPLES AND PROCESS OF ISOLATION OF ELEMENTS

    CENGAGE CHEMISTRY|Exercise Exs 1.1 (True Orfalse Statement)|19 Videos
  • ELECTROCHEMISTRY

    CENGAGE CHEMISTRY|Exercise Archieves Subjective|35 Videos
  • GRIGNARD REAGENTS AND ORGANOMETALLIC REAGENTS

    CENGAGE CHEMISTRY|Exercise Exercises Archives (Linked Comprehension)|1 Videos

Similar Questions

Explore conceptually related problems

Chief ore of Zn is ZnS . The ore is concentrated by froth flotation process and then heated in air to convert ZnS to ZnO . ltntgt 2 ZnS + 3O_(2) rarr 2 ZnO + 2 SO_(2) …(i) ZnO , thus formed is treated with dilute H_(2) SO_(4) . ZnO + H_(2) SO_(4) rarr ZnSO_(4) + H_(2) O ....(ii) On electrolysis of ZnSO_(4(aq)), Zn metal is produced. 2 ZnSO_(4) + H_(2) O rarr 2 Zn + 2H_(2) SO_(4) + O_(2) ....(iii) ZnO on dissolution in NaOH gives

Chief ore of Zn is ZnS . The ore is concentrated by froth flotation process and then heated in air to convert ZnS to ZnO . ltntgt 2 ZnS + 3O_(2) rarr 2 ZnO + 2 SO_(2) …(i) ZnO , thus formed is treated with dilute H_(2) SO_(4) . ZnO + H_(2) SO_(4) rarr ZnSO_(4) + H_(2) O ....(ii) On electrolysis of ZnSO_(4(aq)), Zn metal is produced. 2 ZnSO_(4) + H_(2) O rarr 2 Zn + 2H_(2) SO_(4) + O_(2) ....(iii) How many kilomoles of NaOH are required to dissolve all the ZnO produced in reaction (ii) ?

Chief ore of Zn is ZnS . The ore is concentrated by froth flotation process and then heated in air to convert ZnS to ZnO . ltntgt 2 ZnS + 3O_(2) rarr 2 ZnO + 2 SO_(2) …(i) ZnO , thus formed is treated with dilute H_(2) SO_(4) . ZnO + H_(2) SO_(4) rarr ZnSO_(4) + H_(2) O ....(ii) On electrolysis of ZnSO_(4(aq)), Zn metal is produced. 2 ZnSO_(4) + H_(2) O rarr 2 Zn + 2H_(2) SO_(4) + O_(2) ....(iii) What volume of 98 % H_(2) SO_(4) (by weight, density = 1.8 g//mL ) is required in step (ii) ?

Zn+H_(2)SO_(4)rarrZnSO_(4)+H_(2) Zn undergoes -

The chief are of Zn is the sulphide , ZnS. The are is concentrated by froth floation process and then heated in air to convert Zns to Zno. 2ZnS+30_(2)overset(80%)to 2ZnO+ 2SO_(2) ZnO+H_(2)SO_(4)overset(100%)to ZnSO_(4)+ H_(2) 2ZnSO_(4)+2H_(2)Ooverset(80%)to 2Zn+ 2H_(2)SO_(4)+O_(2) The number of moles of ZnS required for producing 2 moles of Zn will be:

The chief ore of Zn is the sulphide ZnS. The are is concentrated by froth floatation process and then heated in air to convert ZnS to ZnO . 2ZnS+3O_3 80% rarr 2ZnO+2SO. ZnO+H_2SO_4 100% rarr Zn SO_4+H_2O and 2ZnSO_4+2H_2O 80% rarr 2Zn+2Hn+2H_2SO_4+O_2 . The number of moles of ZnS required for producing 2 moles of Zn will be :

In the reaction , Zn+H_(2)SO_(4) to ZnSO_(4) +H_(2) , zinc acts as

The percentage of zinc in ZnSO_(4) . 7H_(2)O is (Zn = 65, S = 32, O = 16 H= 1)