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Knowing the electron gain enthalpy value...

Knowing the electron gain enthalpy values for `O rarr O^(Ө)` and `O rarr O^(2-)` as `- 141 kJ mol^-1` and `+ 702 kJ mol^-1` respectively, how can you account for the formation of a large number of oxides having `O^(2-)` species and not `O^(Ө)` ?

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Althrough the formation of `O^(2-)` anion requires more energy in comparison to the formation of `O^(Ө)` anion (actually energy is released), yet in large number of oxides, oxygen is divalent in nature. This is due to the fact that lattice energies of the oxides having `O^(2-)` anions are very high on account of greater magnitude of electrostatic forces of attraction.
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