Sulphur on reaction with concentrated `HNO_3`. Gives `(A)` which reacts with reacts with `NaOH` gives `(B).(A)` and `(B)` are

Options

A. `H_2 SO_3, Na_2 S_2 O_3`
B. `NO_2, Na_2 S`
C. `H_2 SO_4, Na_2 SO_4`
D. `H_2 S_2 O_3, Na_2 S_2 O_3`

Answer

C

Explanation

`S + HNO_(3) rarr (A)`
`(A) + overset(conc.) (NaOH) rarr (B)`
`S + 6 HNO_(3) rarr underset((A))(H_(2) SO_(4) + 6 NO_(2) + 2 H_(2) O`
`underset((A)) (H_(2) SO_(4)) + 2 NaOH rarr Na_(2) SO_(4) + 2 H_(2) O`.