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Transition metals and many of their comp...

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as
`mu=sqrt(n(n+2))` Bohr magneton
Magnetic moment increases as the number of unpaired electrons increases.
Q. In 3d series the maximum magnetic moment is shown by

A

Sc

B

V

C

Cr

D

Fe

Text Solution

Verified by Experts

The correct Answer is:
c

Cr-atom has maximum number of unpaired electrons i.e., 6. Hence, the magnetic moment is
`sqrt(6xx8)=sqrt(48)BM`
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Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Increasing value of magnetic moment of (I) [Fe(CN)_6]^(4-) (II) [Fe(CN)_6]^(3-) , (III) [Cr(NH_3)_6]^(3+) (IV) [Ni(H_2O)_4]^(2+) is:

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Which among the following ions has maximum value of magnetic moment

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Magnetic moment of [Ni(CN)_4]^(2-) is zero but that of [Ni(H_2O)_4]^(2+) is 2.83BM . is because of :

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. Magnetic moments of Cr(Z=24),Mn^(o+)(Z=35) and Fe^(2+)(Z=36) are x,y and z respectively. Which of the following order is correct?

Transition metals and many of their compounds show paramagnetic behaviour where there are unpaired electron or electrons. The magnetic moment arises from the spin and orbital motions in ions or molecule. Magnetic moment of n unpaired electrons is given as mu=sqrt(n(n+2)) Bohr magneton Magnetic moment increases as the number of unpaired electrons increases. Q. There are three unpaired electrons in [Co(H_2O)_6]^(2+) and calculated value of magnetic moment on the basis of sqrt(n(n+2)) formula is 3.87 BM. which is lower than the expermental value of 4.40 BM. The reason for this difference is due to

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The magnetic moment of a transition metal ion is 3.87BM. The number of unpaired electrons present in it is

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