Calucultae the freezing point of the solution containing `24.8g` solute per kg water for each of the following solutes `K_(f) = 1.86C//m`
(a) `[Co(NH_(3))(NO_(2)_(3)]`
(b) `[Co(NH_(3))_(4)(NO_(2))][Co(NH_(3))(NO_(2))_(4)]`
(c ) `[Co(NH_(3))_(5)(NO_(2))[Co(NH_(3))(NO_(2))_(4)]^(2)`
[Mw of (a) `248g (b) 496 g (c ) 744 g]

Explanation

`DeltaT_(f) = I k_(f) xx m = I k_(f) xx (w_(2) xx 1000)/(Mw_(2) xx w_(1))`
`= 1 xx 1.86 xx (24.8 xx 1000)/(248 xx 1000) = 0.186^(@)C`
`T_(f) = 0-0.186 = - 0.186^(@)C`
(b) `DeltaT_(f) = I k_(f) xx m = 2 xx 1.86 xx (24.8 xx 1000)/(496 xx 1000) = 0.186^(@)C`
`T_(f) = 0 - 0.186 = 0.186^(@)C`
(c) `deltaT_(f) = ik_(f) xx m = 3 xx 1.86 xx (24.8 xx 1000)/(744 xx 1000) = 0.186^(@)C`
`T_(f) = 0 - 0.186 = - 0.186^(@)C` .