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The IUPAC name of the coordination compo...

The `IUPAC` name of the coordination compound `Na_(3)[Ag(S_(2)O_(3))_(2)]` is
(a) Sodium silverthiosulphate (I)
(b) Sodium silverhyposulphate (I)
(c ) Sodium bis [argentothiosulphate(I)]
(d) Sodium bis (thiosulphato)argentite .

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The correct Answer is:
To determine the IUPAC name of the coordination compound \( \text{Na}_3[\text{Ag}(\text{S}_2\text{O}_3)_2] \), we will follow these steps: ### Step 1: Identify the central metal and its oxidation state The central metal in this compound is silver (Ag). To find the oxidation state of silver, we can set up the equation based on the overall charge of the compound. The compound can be broken down as follows: - Sodium (Na) has a +1 charge and there are 3 sodium ions, contributing a total of +3 charge. - The thiosulfate ion (\( \text{S}_2\text{O}_3^{2-} \)) has a -2 charge, and since there are 2 thiosulfate ions, they contribute a total of -4 charge. Setting up the equation: \[ 3(+1) + x + 2(-2) = 0 \] Where \( x \) is the oxidation state of silver. Simplifying this gives: \[ 3 + x - 4 = 0 \implies x = +1 \] Thus, the oxidation state of silver is +1. ### Step 2: Determine the charge of the coordination sphere The coordination sphere is represented by \( [\text{Ag}(\text{S}_2\text{O}_3)_2] \). Since we have already determined that silver is in the +1 oxidation state and each thiosulfate ion contributes -2, we can calculate the overall charge of the coordination sphere. The charge on the coordination sphere is: \[ +1 + 2(-2) = +1 - 4 = -3 \] Thus, the coordination sphere has a -3 charge. ### Step 3: Naming the ligands The ligand \( \text{S}_2\text{O}_3^{2-} \) is known as thiosulfate. Since there are two of these ligands, we use the prefix "bis" to indicate the presence of two identical ligands. ### Step 4: Construct the name of the compound According to IUPAC nomenclature: - The cation (sodium) is named first. - The ligands are named next, followed by the central metal. - Since the coordination sphere has a negative charge, the name of the metal will end with the suffix "-ate". Putting this all together, we have: - Sodium (from \( \text{Na}_3 \)) - Bis (for the two thiosulfate ligands) - Thiosulfate (the ligand name) - Argentate (for silver in the coordination sphere) Thus, the complete IUPAC name is: **Sodium bis(thiosulfato)argentate(I)** ### Step 5: Final answer The correct answer from the options provided is: **(d) Sodium bis(thiosulfato)argentate(I)** ---
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