Write the `IUPAC` nomenclature of the given complex along with its hybridisation and structure
`Ca[Cr(NO)(NH_(3))(CN)_(4)],mu_(spin)=1.73BM` .

Explanation

`mu_("spin")` of the complex is `1.73BM`
`mu= sqrt(n (n + 2)) = 1.73implies n =1`
Thus chromium ion has one unpaired electron
Case I If NO is neutral
`overset(2+)(Co)[overset(2+)(Cr)overset(0)(NO) (overset(0)(NH)_(3))overset(-4)((CN)_(4)]]^(2-)`
Then `Cr^(2+)` under the influence of strong field ligand `(CN^(Θ))` , it would correspond to 2 unpaired electrons
`Cr(Z =24)implies 3d^(5)4s^(1),Cr^(2+) implies 3d^(4)4s^(1)`

But the complex shows spin magnetic moment `(mu)` which corresponds to one unpaired electron
So,the ligand `NO` is `+1` charged and teh `IUPAC` name of the compounds is Calcium amminetetracyano nitrosonium chromate(I)
.