One cationic complex has to isomers `A` and `B` Each has one `Co^(3+)` five `NH_(3)` one `CI^(Θ)` and one `SO_(4)^(2-)` stoichiometically A give white precipitate with `BaCI_(2)` white `B` gives white precipitate with `AgNO_(3)`
` (B)` can be .

Options

A. `[Co(NH_(3))_(5)SO_(4)]CI`
B. `[CO(NH_(3))_(5)CI]SO_(4)`
C. `[Co(NH_(3))_(3)CI(SO_(4))]2NH_(3)`
D. None of these

Answer

A

Explanation

B gives white ppt `AgNO_(3)` so `CI^(Θ)` is negative counter ion Hence answer is (c )