`[Co(NH_(3))_(5)SO_(4)]Br` and `[Co(NH_(3))_(5)Br]SO_(4)` shown _________isomerism .

Answer

To determine the type of isomerism exhibited by the complexes `[Co(NH₃)₅SO₄]Br` and `[Co(NH₃)₅Br]SO₄`, we can follow these steps:

### Step 1: Identify the Coordination Compounds
The two complexes are:
1. `[Co(NH₃)₅SO₄]Br`
2. `[Co(NH₃)₅Br]SO₄`

### Step 2: Analyze the Composition
Both complexes contain cobalt (Co) as the central metal ion, ammonia (NH₃) as a ligand, and different counter ions (Br⁻ and SO₄²⁻).

### Step 3: Determine the Position of Counter Ions
In the first complex `[Co(NH₃)₅SO₄]Br`, the sulfate ion (SO₄²⁻) is part of the coordination sphere, while the bromide ion (Br⁻) is outside the coordination sphere. In the second complex `[Co(NH₃)₅Br]SO₄`, the bromide ion is part of the coordination sphere, and the sulfate ion is outside.

### Step 4: Consider Ionization in Solution
When these complexes are dissolved in solution, they will dissociate into their respective ions:
- For `[Co(NH₃)₅SO₄]Br`, it dissociates into `[Co(NH₃)₅SO₄]²⁺` and `Br⁻`.
- For `[Co(NH₃)₅Br]SO₄`, it dissociates into `[Co(NH₃)₅Br]²⁺` and `SO₄²⁻`.

### Step 5: Identify the Type of Isomerism
Since the two complexes yield different ions upon dissociation, they exhibit a type of isomerism known as ionization isomerism. This occurs when two or more coordination compounds have the same formula but differ in the identity of the ions that can be released into solution.

### Conclusion
Thus, the two complexes `[Co(NH₃)₅SO₄]Br` and `[Co(NH₃)₅Br]SO₄` show **ionization isomerism**.

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