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A metal chloride on heating with K(2)C...

A metal chloride on heating with `K_(2)Cr_(2)O_(7)` gives a yellow ppt insoluble in acetic acid .The metal may be

A

Hg

B

Zn

C

Pb

D

Ag

Text Solution

Verified by Experts

The correct Answer is:
c
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CENGAGE CHEMISTRY-QUALITATIVE INORGANIC SALT ANALYSIS-Ex 8.2
  1. Pb has been placed in groups I and II because

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  2. With Fe^(3+) ions [Fe(CN)(6)]^(4-) gives prussian blue colouration ...

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  3. A metal chloride on heating with K(2)Cr(2)O(7) gives a yellow ppt i...

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  4. With Zn^(2+) ions [Fe(CN)(6)]^(4-) ions gives …ppt

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  5. Which one among the following pairs of ions cannot be seprated ...

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  6. Which of the following pairs of ions would be expected to form pr...

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  7. Which one of the following can be used in place of Nh(4)CI for ident...

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  8. Cone HNO(3) is added before proceeding to test for group II This i...

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  9. In IV th group the ppt of Mn(OH)(2) in excess of NaOH , turns brown ...

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  10. Mg is not precipitate in group V because

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  11. In group V ,(NH(4))(2)CO(3) is added to precipitate out the carbonate...

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  12. DMG gives a rosy red crystalline ppt with

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  13. H(2)S in the presence of HCI precipitates group II radicals but not...

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  14. Prussian's blue is formed when Fe^(+2) ions are added to K(4)[Fe(CN...

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  15. Turnbull's blue is formed when Fe^(+2) ions are added to K(3)[Fe(CN)(...

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  16. If group IV the ppt of Zn(OH)(2) dissolve in excess of NaOH due to t...

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  17. Br(2) water in NaOH soin .Oxidises Mn(OH)(2) to a…. Ppt due to the fo...

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  18. Brown ppt ,of MnO(OH) on boiling with PbO(2) and cone HNO(3) yields...

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  19. A precipitate of ……would be obtained on adding HCI to a solution of ...

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  20. A precipitate of ……would be obtained on adding HCI to a solution of ...

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