Explain `[Co(NH_3)_6]^(3+)` is an inner orbital complex whereas `[Ni(NH_3)_6]^(2+)` is an outer orbital complex.

Explanation

To explain why `[Co(NH_3)_6]^(3+)` is an inner orbital complex while `[Ni(NH_3)_6]^(2+)` is an outer orbital complex, we need to analyze the electronic configurations and hybridization of the central metal ions in each complex. Here is a step-by-step solution:

### Step 1: Determine the oxidation states and electronic configurations of the central metal ions.

- **Cobalt in `[Co(NH_3)_6]^(3+)`:**
- Cobalt (Co) has an atomic number of 27. Its ground state electronic configuration is `[Ar] 3d^7 4s^2`.
- In the +3 oxidation state, cobalt loses 3 electrons. The configuration becomes:
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