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The decreasing order of - I effect of th...

The decreasing order of `- I` effect of the orbitals is :
(I) `sp`
(II) `sp^2`
(III) `sp^3`.

A

`I gt II gt III`

B

`III gt II gt I`

C

`I gt III gt II`

D

`II gt III gt I`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) The more the `s` character, the more is the penetration effect of `s` orbital towards the nucleus, and hence more `overline e`-withdrawing effect. So `sp(50 % s) gt sp^2(33 % s) gt sp^3 (25 % s)`.
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